WealthWiseGuys Practical Mathematics

Chapter 14

Installment Purchases, Credit Cards, and Consumer Debt

Compare borrowing costs, read statements, and plan repayment

A small monthly payment can hide a surprisingly large total cost. Learn to compare installment offers, calculate credit card charges, and explain how payments reduce debt. All people, prices, rates, and contract terms in this chapter are hypothetical; round money to the nearest cent.

14.1

The Real Cost of an Installment Purchase

Learning objectives

After this section you will be able to:

  1. Calculate the amount financed after a down payment.
  2. Find total payments, finance charges, and total purchase cost.
  3. Compare offers using both affordability and total cost.

Real-life situation

A computer for school and creative work

A Philadelphia student compares two payment plans for a $900 computer. Both fit the student's monthly budget, but the smaller advertised payment is not enough information to choose.

OfferCash priceDown paymentMonthly paymentMonths
A$900$180$6512
B$900$100$8810
Figure 14.1 Hypothetical installment offers; no tax or additional fees

The concept

An installment purchase spreads payment across a stated number of scheduled payments. The cash price is the price paid without financing. A down payment reduces the amount that must be financed; it does not disappear from your total spending.

Multiply the regular payment by the number of payments to find the scheduled payment total. When all borrowing charges are included in those payments, subtract the amount financed to find the finance charge. Add the down payment to the scheduled payments to find total purchase cost.

For these simplified examples, there are no taxes, insurance products, balloon payments, or separate fees unless stated. Real disclosures may include these items, so identify every required payment before comparing offers. Do not add a fee twice if it is already included in the payment schedule.

A lower monthly payment may simply mean a longer repayment period. Compare total cost and timing as well as monthly affordability. Finance charge divided by amount financed is a cost percentage for the whole contract, not the annual percentage rate, because principal is repaid during the term.

The Real Cost of an Installment Purchase: solution map

  1. 1

    Identify the question

    Use Figure 14.1 to find Offer A's amount financed, finance charge, and total purchase cost.

  2. 2

    Calculation 1

    Amount financed: $900 − $180 = $720.

  3. 3

    Calculation 2

    Scheduled payments: 12 × $65 = $780.

  4. 4

    Calculation 3

    Finance charge: $780 − $720 = $60.

  5. 5

    Calculation 4

    Total purchase cost: $180 + $780 = $960.

  6. 6

    Interpret and check

    The student borrows $720, pays a $60 finance charge, and spends $960 altogether.

Figure 14.1.V The Real Cost of an Installment Purchase: solution map. Hypothetical teaching data.

Money Words

Plain-language words you will use in this lesson — learn them before we reach the formulas.

  • credit card

    A card that lets you borrow up to a limit and repay over time, usually with interest.

  • APR

    Annual percentage rate — the yearly cost of borrowing, including interest and some fees, shown as a percent.

  • minimum payment

    The smallest amount due on a credit card bill each month; paying only this keeps you in debt longer.

Key terms

Cash price
The price of an item before borrowing charges.
Down payment
Money paid at the start toward the purchase price.
Amount financed
The amount borrowed to complete the purchase.
Finance charge
The dollar cost of borrowing under the stated terms.
Installment
One scheduled payment in a series.

Formulas & rules

  • Amount financed

    Amount financed = cash price − down payment

  • Payment total

    Payment total = payment amount × number of payments

  • Finance charge

    Finance charge = payment total − amount financed

    Assumes all borrowing charges are in the scheduled payments.

  • Total purchase cost

    Total purchase cost = down payment + payment total + separate required fees

Worked examples

Example 1Unpack Offer A

Use Figure 14.1 to find Offer A's amount financed, finance charge, and total purchase cost.

Solution

  1. 1Amount financed: $900 − $180 = $720.
  2. 2Scheduled payments: 12 × $65 = $780.
  3. 3Finance charge: $780 − $720 = $60.
  4. 4Total purchase cost: $180 + $780 = $960.

Answer: The student borrows $720, pays a $60 finance charge, and spends $960 altogether.

Example 2Compare the second offer

Find Offer B's total cost and compare it with Offer A.

Solution

  1. 1Amount financed: $900 − $100 = $800.
  2. 2Scheduled payments: 10 × $88 = $880.
  3. 3Finance charge: $880 − $800 = $80.
  4. 4Total cost: $100 + $880 = $980.
  5. 5Difference: $980 − $960 = $20; Offer B also requires the larger monthly payment.

Answer: Offer A costs $20 less; Offer B requires $80 less upfront but $23 more each month.

Practice exercises 14.1

  1. What percent of the $900 cash price is Offer A's $180 down payment?
  2. A genuinely fee-free, zero-interest plan finances $720 over 12 equal payments. Find each payment.
  3. Offer A also requires a separate $25 setup fee not included in its payments. Find its revised total cost.
  4. Find $60 ÷ $720 as a percent. Explain why it is not Offer A's APR.
  5. Your monthly payment limit is $70. Which original offer meets it, and what else should you check?

Recap quiz 14.1

1. A $900 item has a $180 down payment. How much is financed?
2. Twelve payments of $65 total:
3. Which comparison best reveals overall purchase spending?

Section 14.1 recap

  • Separate the cash price, amount financed, finance charge, and total purchase cost.
  • A manageable payment is necessary, but it does not prove an offer is inexpensive.
Answer key with explanations: Section 14.1

Practice exercises

  1. $180 ÷ $900 × 100 = 20%. The down payment covers one-fifth of the cash price.
  2. $720 ÷ 12 = $60. With no finance charge, all $720 of payments repay principal.
  3. $180 + 12 × $65 + $25 = $985. Count the separate fee once.
  4. $60 ÷ $720 × 100 ≈ 8.33%. This compares the full contract charge with the initial amount financed; it ignores the timing of declining balances, so it is not APR.
  5. Offer A's $65 is at or below $70; Offer B's $88 exceeds it by $18. Also check the $180 down payment, total cost of $960, and any terms or fees not shown.

Recap quiz

  1. $720: $900 − $180 = $720.
  2. $780: 12 × $65 = $780; the down payment is separate.
  3. Down payment plus all required payments and separate fees: Every required dollar belongs in total purchase cost.
14.2

Credit Card Balances and Finance Charges

Learning objectives

After this section you will be able to:

  1. Calculate a weighted average daily balance.
  2. Estimate interest using a stated daily periodic rate.
  3. Reconcile purchases, payments, interest, and ending balance.

Real-life situation

Two balances during one billing cycle

A hypothetical card statement has a $600 balance for the first 10 days and a $900 balance for the next 20 days. A $100 payment posts at the cycle's end, after the daily balance measurement used here.

Period or itemAmount or duration
First balance$600 for 10 days
After a purchase$900 for 20 days
New purchase$300
End-of-cycle payment$100
Daily interest conventionAPR ÷ 365; no daily compounding
Figure 14.2 Simplified 30-day card cycle at 24% APR

The concept

A credit card balance changes when purchases, payments, credits, fees, and interest post. A statement summarizes activity over a billing cycle, while a current online balance may include later transactions. Always match the dates before comparing the two.

An average daily balance weights each balance by the number of days it applied. Multiply each balance by its days, add the products, and divide by the cycle's total days. Simply averaging the highest and lowest balances works only when they lasted equally long.

This lesson uses a simplified interest method: average daily balance × APR ÷ 365 × cycle days, with no daily compounding. Convert APR from percent to decimal before calculating and round the final charge to cents. Actual card agreements can use other conventions and separate rates for different balance types.

A grace period may allow eligible purchases to avoid interest when the required statement balance is paid by its due date. Eligibility and exclusions depend on the agreement; cash advances may be treated differently. Our interest examples assume no grace-period benefit applies.

Credit Card Balances and Finance Charges: solution map

  1. 1

    Identify the question

    Find the average daily balance and interest for Figure 14.2.

  2. 2

    Calculation 1

    First period: $600 × 10 = 6,000 dollar-days.

  3. 3

    Calculation 2

    Second period: $900 × 20 = 18,000 dollar-days.

  4. 4

    Calculation 3

    Average daily balance: (6,000 + 18,000) ÷ 30 = $800.

  5. 5

    Calculation 4

    Daily rate: 0.24 ÷ 365; retain full precision.

  6. 6

    Calculation 5

    Interest: $800 × (0.24 ÷ 365) × 30 ≈ $15.78.

  7. 7

    Interpret and check

    Average daily balance is $800; the simplified cycle interest is $15.78.

Figure 14.2.V Credit Card Balances and Finance Charges: solution map. Hypothetical teaching data.

Money Words

Plain-language words you will use in this lesson — learn them before we reach the formulas.

  • installment plan

    Paying for something in a set number of equal payments over time.

  • late fee

    An extra charge when a payment arrives after its due date.

  • grace period

    A short time after the due date before a fee or interest charge applies.

Key terms

Billing cycle
The period covered by one statement.
APR
Annual percentage rate; an annualized borrowing-rate disclosure.
Average daily balance
The sum of daily balances divided by the number of days.
Daily periodic rate
The daily interest rate specified by the agreement.
Grace period
A conditional interval in which eligible purchases may avoid interest.

Formulas & rules

  • Weighted balance

    Average daily balance = sum of (balance × days) ÷ cycle days

  • Daily rate

    Daily rate = APR as a decimal ÷ 365

    The convention assumed in this section.

  • Cycle interest

    Interest = average daily balance × daily rate × cycle days

  • Statement reconciliation

    Ending balance = beginning balance + purchases + fees + interest − payments − credits

Worked examples

Example 1Weight balances by time

Find the average daily balance and interest for Figure 14.2.

Solution

  1. 1First period: $600 × 10 = 6,000 dollar-days.
  2. 2Second period: $900 × 20 = 18,000 dollar-days.
  3. 3Average daily balance: (6,000 + 18,000) ÷ 30 = $800.
  4. 4Daily rate: 0.24 ÷ 365; retain full precision.
  5. 5Interest: $800 × (0.24 ÷ 365) × 30 ≈ $15.78.

Answer: Average daily balance is $800; the simplified cycle interest is $15.78.

Example 2Reconcile the statement

Use a $600 beginning balance, $300 purchase, $15.78 interest, $100 payment, and no fees or credits.

Solution

  1. 1Before interest or payment: $600 + $300 = $900.
  2. 2Add interest: $900 + $15.78 = $915.78.
  3. 3Subtract the payment: $915.78 − $100 = $815.78.

Answer: The ending statement balance is $815.78.

Practice exercises 14.2

  1. A $900 balance lasts all 30 days. What is its average daily balance?
  2. For a separate simplified monthly model, estimate one month's interest on $900 at 24% APR using APR ÷ 12.
  3. A statement has $900 owed on a $3,000 limit. Find utilization.
  4. Why is ($600 + $900) ÷ 2 = $750 not the average balance in Figure 14.2?
  5. A $100 payment posts earlier instead of at the end. With all else unchanged, would interest under the daily-balance method rise or fall?

Recap quiz 14.2

1. Which APR decimal represents 24%?
2. Which transaction usually reduces the balance?
3. Why weight daily balances?

Section 14.2 recap

  • Weight balances by days and use the interest convention actually stated.
  • A statement balance is a dated accounting total, not necessarily today's balance.
Answer key with explanations: Section 14.2

Practice exercises

  1. ($900 × 30) ÷ 30 = $900. With no changes, the average equals the constant balance.
  2. Monthly rate = 0.24 ÷ 12 = 0.02. Interest = $900 × 0.02 = $18. This monthly convention differs from the daily convention.
  3. $900 ÷ $3,000 × 100 = 30%. Utilization compares the balance with the available credit limit, not with income.
  4. The $900 balance lasted 20 days, twice as long as $600. Weighting gives (600 × 10 + 900 × 20) ÷ 30 = $800, not $750.
  5. It would fall: each affected daily balance is $100 lower. The reduction equals $100 × affected days × (0.24 ÷ 365), rounded under the agreement's rules.

Recap quiz

  1. 0.24: 24 ÷ 100 = 0.24.
  2. Payment: A payment is subtracted when reconciling the balance.
  3. Balances can apply for different lengths of time: Dollar-days reflect both the balance and its duration.
14.3

Building a Consumer Debt Repayment Plan

Learning objectives

After this section you will be able to:

  1. Separate interest from principal reduction.
  2. Compare ordinary and larger payments.
  3. Measure scheduled debt payments relative to income.

Real-life situation

Make progress, not just payments

A part-time worker has a $1,000 balance at a hypothetical monthly rate of 2%. There are no new purchases or fees, and interest is added before the month-end payment.

Same debt, different payments

  • Starting balance: $1,000.00
  • Monthly interest: 2% × $1,000 = $20.00
  • Pay $120: principal falls $100; ending balance $900
  • Pay $220: principal falls $200; ending balance $800
Figure 14.3 Two hypothetical first-month repayment choices

The concept

A payment does not necessarily reduce principal by its full amount. Under this section's model, interest is added first, then the payment covers that interest and reduces the remaining debt. If a payment is less than the interest charged, the balance grows even without new purchases.

A repayment forecast needs explicit assumptions: the rate, payment date, payment amount, fees, and whether borrowing continues. With a fixed positive payment and no new charges, a falling balance usually produces a smaller next interest charge when the rate stays constant.

For several debts, list each balance, rate, minimum payment, and due date. Keep required payments in the plan before deciding where any extra money goes. Directing extra money to a higher-rate balance generally reduces interest under comparable terms, while a smallest-balance approach emphasizes eliminating accounts; fees and special terms can change the comparison.

A payment-to-income ratio measures how much income is already committed to debt payments. State whether the denominator is gross or take-home income. The ratio is a budgeting indicator, not an approval guarantee or a universal safety cutoff; housing, food, transportation, and emergency needs still matter.

Ending debt after different payments

After $120 payment$ 900
After $220 payment$ 800

Bars share a zero baseline.

Figure 14.3.V Ending debt after different payments. Hypothetical teaching data.

Money Words

Plain-language words you will use in this lesson — learn them before we reach the formulas.

  • credit limit

    The most you can borrow on a credit card or credit line.

  • statement balance

    The amount owed on a credit account as of the statement date.

  • credit score

    A number that estimates how reliably someone repays debts.

Key terms

Principal
The unpaid borrowed amount, excluding newly calculated interest in this model.
Principal reduction
The portion of a payment that lowers the debt after interest.
Minimum payment
The smallest payment required by the agreement for that period.
Negative amortization
Growth in a balance because payments do not cover added interest.
Payment-to-income ratio
Scheduled debt payments divided by a stated income measure.

Formulas & rules

  • Monthly interest

    Interest = starting balance × monthly rate

  • Principal reduction

    Principal reduction = payment − interest

    Assumes no other charges.

  • Next balance

    Next balance = starting balance + interest − payment

  • Payment burden

    Payment-to-income percent = monthly debt payments ÷ monthly income × 100

Worked examples

Example 1Track an ordinary payment

Find the balance after paying $120 on the $1,000 debt, then find the next month's interest.

Solution

  1. 1First-month interest: $1,000 × 0.02 = $20.
  2. 2Principal reduction: $120 − $20 = $100.
  3. 3Ending balance: $1,000 − $100 = $900.
  4. 4Next month's interest: $900 × 0.02 = $18.

Answer: The balance falls to $900; the following month's interest is $18 before its payment.

Example 2Add money to the payment

Instead pay $220 in the first month. Compare the ending balance with the $120 plan.

Solution

  1. 1Interest is still $1,000 × 0.02 = $20 because the payment occurs at month-end.
  2. 2Principal reduction: $220 − $20 = $200.
  3. 3Ending balance: $1,000 − $200 = $800.
  4. 4Compared with $900, the ending balance is $100 lower.

Answer: The extra $100 payment lowers principal by an extra $100; it also lowers later interest.

Practice exercises 14.3

  1. What payment lowers the first month's balance from $1,000 to $850 at 2% monthly interest?
  2. What happens if the first payment is only $15?
  3. Find the payment-to-take-home-income ratio for $120 in debt payments and $1,500 take-home pay.
  4. Find next month's interest after the larger-payment plan leaves an $800 balance.
  5. A plan predicts a $900 ending balance, but you add a $50 purchase after interest is calculated. Recompute the ending balance.

Recap quiz 14.3

1. A $120 payment includes $20 interest. Principal reduction is:
2. Which assumption is essential to the illustrated declining-balance forecast?
3. If interest is $20 and payment is $15, the balance:

Section 14.3 recap

  • Subtract interest from a payment to see actual principal reduction.
  • A useful repayment plan includes required payments, living costs, and clear assumptions.
Answer key with explanations: Section 14.3

Practice exercises

  1. Interest is $20, so the amount before payment is $1,020. Required payment = $1,020 − $850 = $170.
  2. Interest is $20. Ending balance = $1,000 + $20 − $15 = $1,005, a $5 increase.
  3. $120 ÷ $1,500 × 100 = 8%. This leaves 92% before considering other spending, not necessarily 92% available to save.
  4. $800 × 0.02 = $16. Compared with $18 on $900, this saves $2 in the next month.
  5. $1,000 + $20 + $50 − $120 = $950. The original $900 forecast assumed no new purchases.

Recap quiz

  1. $100: $120 − $20 = $100.
  2. No new purchases or fees: New charges or changed terms require a new forecast.
  3. Rises $5: $20 − $15 = $5 of unpaid interest increases the balance.

Chapter 14 Organizer and Review

Chapter Organizer

Every section at a glance: key formulas, key terms, and the main idea.

  • 14.1 The Real Cost of an Installment Purchase

    Key formulas

    • Amount financed: Amount financed = cash price − down payment
    • Payment total: Payment total = payment amount × number of payments
    • Finance charge: Finance charge = payment total − amount financed
    • Total purchase cost: Total purchase cost = down payment + payment total + separate required fees

    Key terms

    Cash price, Down payment, Amount financed, Finance charge, Installment

    Remember

    Separate the cash price, amount financed, finance charge, and total purchase cost.

  • 14.2 Credit Card Balances and Finance Charges

    Key formulas

    • Weighted balance: Average daily balance = sum of (balance × days) ÷ cycle days
    • Daily rate: Daily rate = APR as a decimal ÷ 365
    • Cycle interest: Interest = average daily balance × daily rate × cycle days
    • Statement reconciliation: Ending balance = beginning balance + purchases + fees + interest − payments − credits

    Key terms

    Billing cycle, APR, Average daily balance, Daily periodic rate, Grace period

    Remember

    Weight balances by days and use the interest convention actually stated.

  • 14.3 Building a Consumer Debt Repayment Plan

    Key formulas

    • Monthly interest: Interest = starting balance × monthly rate
    • Principal reduction: Principal reduction = payment − interest
    • Next balance: Next balance = starting balance + interest − payment
    • Payment burden: Payment-to-income percent = monthly debt payments ÷ monthly income × 100

    Key terms

    Principal, Principal reduction, Minimum payment, Negative amortization, Payment-to-income ratio

    Remember

    Subtract interest from a payment to see actual principal reduction.

Cumulative Review

Mixed practice from this chapter and the two chapters before it.

  1. Section 14.1

    Your monthly payment limit is $70. Which original offer meets it, and what else should you check?

    Show answer

    Offer A's $65 is at or below $70; Offer B's $88 exceeds it by $18. Also check the $180 down payment, total cost of $960, and any terms or fees not shown.

  2. Section 14.2

    A $100 payment posts earlier instead of at the end. With all else unchanged, would interest under the daily-balance method rise or fall?

    Show answer

    It would fall: each affected daily balance is $100 lower. The reduction equals $100 × affected days × (0.24 ÷ 365), rounded under the agreement's rules.

  3. Section 14.3

    A plan predicts a $900 ending balance, but you add a $50 purchase after interest is calculated. Recompute the ending balance.

    Show answer

    $1,000 + $20 + $50 − $120 = $950. The original $900 forecast assumed no new purchases.

  4. Review of Section 12.3

    Find present value of $1,210.00 due in 2 years using 10% annually compounded.

    Show answer

    Future value is $1,210.00; i = 0.10; n = 2. Accumulation factor = 1.10² = 1.21. PV = 1210 ÷ 1.21 = $1,000.00. Check by multiplying the unrounded PV by 1.21 to recover the future amount.

  5. Review of Section 13.3

    Find equal month-end deposits to reach at least $1,000.00 after 3 deposits at an assumed 1% monthly rate.

    Show answer

    Target = $1,000.00; i = 0.01; n = 3. Accumulation factor = (1.01³ − 1) ÷ 0.01 = 3.0301. Exact R = 1000 ÷ 3.0301 = 330.022111481… . Round up to cents: $330.03. Check: rounded deposit × 3.0301 = $1,000.02.

All prices, stores, people, and accounts in this chapter are hypothetical and for teaching only. Product references are generic categories; no brand endorses or is endorsed by this textbook.