Exponents and Compound Growth
Learning objectives
After this section you will be able to:
- Place the relevant cash flows on a timeline.
- Calculate the modeled value using a matching periodic rate.
- Interpret the result and identify the model's assumptions.
Real-life situation
A student savings timeline
A Philadelphia student uses a hypothetical fixed-rate model to compare cash flows for future school or equipment costs.
A student savings timeline
- Initial deposit: $1,000.00
- Annual rate: 5%; annual compounding; 2 years
- Year 1: $1,050.00; year 2: $1,102.50
The concept
An exponent tells how many times a factor is multiplied by itself. In (1 + i)ⁿ, i is the rate per compounding period and n counts periods, not necessarily years. Square means two factors; it does not mean multiply the factor by two.
Compound interest adds each period's interest to the balance, so later interest is earned on both original principal and earlier interest. At a positive fixed rate this produces more growth than simple interest over multiple periods.
For a single deposit with no withdrawals or fees, multiply principal by the accumulation factor. Keep all calculator digits until the final result. These models round money only at the end; a provider that rounds each period can produce a slightly different result.
All rates and cash flows are hypothetical classroom assumptions, not investment advice or promised returns. Retain full precision through intermediate calculations and round final money to cents; for a minimum savings target, round the deposit upward instead. Draw the timeline before calculating and explain what the result means.
Compound interest timeline
Year 0
$1,000.00
Principal
Year 1
$1,050.00
Interest: $50.00
Year 2
$1,102.50
Interest: $52.50
- Year 0: deposit $1,000.
- Year 1: multiply by 1.05; $50 interest gives $1,050.
- Year 2: multiply the new balance by 1.05; $52.50 interest gives $1,102.50. Growth is not guaranteed in an investment.
Original WealthWiseGuys diagram · Hypothetical teaching quantities.
Money Words
Plain-language words you will use in this lesson — learn them before we reach the formulas.
compound interest
Interest earned on both the original amount and the interest already earned.
present value
What a future amount of money is worth today at a given interest rate.
future value
What an amount of money today will be worth at a later date with interest.
Key terms
- Exponent
- The number of repeated factors.
- Periodic rate
- The rate applying in one compounding period.
- Compound interest
- Interest on principal and previously credited interest.
- Future value
- The modeled balance at a later date.
Formulas & rules
Exponents and Compound Growth
FV = P × (1 + i)ⁿ
Related relationship
Interest = FV − P
Worked examples
Find future value of $1,000.00 at 5% annually compounded for 2 years.
Solution
- 1Use P = $1,000.00, i = 0.05, and n = 2.
- 2Growth factor = 1.05² = 1.1025.
- 3FV = 1000 × 1.1025 = $1,102.50.
- 4Interest = $1,102.50 − $1,000.00 = $102.50.
Answer: $1,102.50
Find future value of $2,000.00 at 5% annually compounded for 2 years.
Solution
- 1Use P = $2,000.00, i = 0.05, and n = 2.
- 2Growth factor = 1.05² = 1.1025.
- 3FV = 2000 × 1.1025 = $2,205.00.
- 4Interest = $2,205.00 − $2,000.00 = $205.00.
Answer: $2,205.00
Practice exercises 12.1
- Find future value of $1,000.00 at 5% annually compounded for 2 years.
- Find future value of $2,000.00 at 5% annually compounded for 2 years.
- Find future value of $500.00 at 5% annually compounded for 2 years.
- Find future value of $3,000.00 at 5% annually compounded for 2 years.
- Find future value of $4,000.00 at 5% annually compounded for 2 years.
Recap quiz 12.1
Section 12.1 recap
- Draw the timeline and match the rate to each interval.
- Keep intermediate precision; distinguish modeled values from guaranteed outcomes.
Answer key with explanations: Section 12.1
Practice exercises
- Use P = $1,000.00, i = 0.05, and n = 2. Growth factor = 1.05² = 1.1025. FV = 1000 × 1.1025 = $1,102.50. Interest = $1,102.50 − $1,000.00 = $102.50.
- Use P = $2,000.00, i = 0.05, and n = 2. Growth factor = 1.05² = 1.1025. FV = 2000 × 1.1025 = $2,205.00. Interest = $2,205.00 − $2,000.00 = $205.00.
- Use P = $500.00, i = 0.05, and n = 2. Growth factor = 1.05² = 1.1025. FV = 500.0 × 1.1025 = $551.25. Interest = $551.25 − $500.00 = $51.25.
- Use P = $3,000.00, i = 0.05, and n = 2. Growth factor = 1.05² = 1.1025. FV = 3000 × 1.1025 = $3,307.50. Interest = $3,307.50 − $3,000.00 = $307.50.
- Use P = $4,000.00, i = 0.05, and n = 2. Growth factor = 1.05² = 1.1025. FV = 4000 × 1.1025 = $4,410.00. Interest = $4,410.00 − $4,000.00 = $410.00.
Recap quiz
- $1,102.50: Use P = $1,000.00, i = 0.05, and n = 2. Growth factor = 1.05² = 1.1025. FV = 1000 × 1.1025 = $1,102.50. Interest = $1,102.50 − $1,000.00 = $102.50.
- Match the rate period to the timeline: The periodic rate and period count must describe the same interval; assumptions are not guarantees.
- Retain full precision: Retaining calculator precision avoids accumulating rounding errors; round the final monetary result.